Solve the following pair of linear equations | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given equations are:$(1)$ $8x + 5y = 9$$(2)$ $3x + 2y = 4$From equation $(2)$,we can express $y$ in terms of $x$:$2y = 4 - 3x$$y = \frac{4 - 3x}{2

Vedclass · Accepted Answer

$(-2, 5)$

Vedclass · Answer

(A) Given equations are:$(1)$ $8x + 5y = 9$$(2)$ $3x + 2y = 4$From equation $(2)$,we can express $y$ in terms of $x$:$2y = 4 - 3x$$y = \frac{4 - 3x}{2}$Substitute this value of $y$ into equation $(1)$:$8x + 5(\frac{4 - 3x}{2}) = 9$Multiply the entire equation by $2$ to eliminate the fraction:$16x + 5(4 - 3x) = 18$$16x + 20 - 15x = 18$$x + 20 = 18$$x = 18 - 20$$x = -2$Now,substitute $x = -2$ back into the expression for $y$:$y = \frac{4 - 3(-2)}{2}$$y = \frac{4 + 6}{2}$$y = \frac{10}{2}$$y = 5$Thus,the solution is $(x, y) = (-2, 5)$.

Solve the following pair of linear equations by the method of substitution: $8x + 5y = 9$ and $3x + 2y = 4$.

Similar Questions

Find the value of $k$ for which the following pair of linear equations has infinitely many solutions:
$kx + 3y = k - 3$
$12x + ky = k$

Solve the following pairs of equations:
$43x + 67y = -24$
$67x + 43y = 24$

Solve the following pair of linear equations:
$21x + 47y = 110$
$47x + 21y = 162$

The sum of the digits of a two-digit number is $6$. The number obtained by interchanging the digits is $18$ less than the original number. Find the original number.

Solve the following pair of linear equations using the cross-multiplication method:
$5x + 2y = 10$
$4x + 3y - 1 = 0$

Vedclass Test Series

Exam Paper Generator

Online Exam Module